Question

The line above goes through points (-4,-1)and(0,2). What is the equation of the line?

A. Y=(3/4)x-2
B. Y=(3/2)x+3
C. Y=(4/3)x+2
D. Y=(3/4)x+2

Answer 1

@garrett_payne think you could explain this to me as well?

Answer 2

very similar thing here.
find slope
then intercept

Answer 3

How would I do that for this one?

Answer 4

pick point 1 and point 2 then find (Y2-y1)/(x2-X1)
remember it's written as (X,Y)

Answer 5

so

-4 - -1
--------
0 - 2

Answer 6

??

Answer 7

no you're writing it as (x1-y1) /(x2-y2)

Answer 8

first write what Y1,Y2, X1 and X2 are

Answer 9

Y1=-4,Y2=-1, X1=0,X2=2

Answer 10

no, the numbers are read as (x,Y)
so say (-4,-1) is point 1 then -4 is x and -1 is y

Answer 11

Okay

Answer 12

\[m = y _{2}-y _{1}/x _{2}-x _{1}\]

Answer 13

where m is the gradient of the line, try doing it now :)

Answer 14

how are you doing with this @kaek98

Answer 15

Not great

Answer 16

I dont understand any of this

Answer 17

look at my last post call it point one
then do the same for point 2

Answer 18

so 0 is x and 2 is y

Answer 19

yes,

Answer 20

now that you know Y1, X1, Y2 and X2 plug them in the slope equation I showed you

Answer 21

(-4-0)/(-1-2)

Answer 22

close but backwards
(-1-2)/(-4-0)
remember x is first then y

Answer 23

slope is -3/-4 or 0.75

Answer 24

Okay

Answer 25

that value is m (slope)
remember y=mx+b plug in either point
say (0,2)
y=2
m=3/4
x=0 and find b

Answer 26

2

Answer 27

Am I right? @garrett_payne

Answer 28

yes you are.
You can do it just try to think about what the numbers mean and not get flustered because you think you're bad a math

Answer 29

Thanks :)