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OpenStudy (anonymous):
Based on the following results what is the experimental probability of rolling a 1?
Outcome Frequency
1 6
2 2
3 2
4 3
5 2
6 0
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OpenStudy (anonymous):
@garrett_payne
OpenStudy (anonymous):
Add up all the frequencies. Divide the frequency of the target outcome by the sum of all frequencies.
OpenStudy (anonymous):
let me try..
OpenStudy (anonymous):
so add up 1-6/6?
OpenStudy (anonymous):
No.. divide 6 by 6+2+2+3+...
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OpenStudy (anonymous):
I know. 1-6 means all the numbers between 0 and 6.
OpenStudy (anonymous):
1+2+3+4+5+6/6
OpenStudy (anonymous):
?
OpenStudy (anonymous):
divide x by y means x / y not y / x
OpenStudy (anonymous):
I got '16'.
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OpenStudy (anonymous):
It makes no sense for probability to be over 1.
OpenStudy (anonymous):
wait,sorry.
OpenStudy (anonymous):
can you give me the equation?
OpenStudy (anonymous):
o wait, you mean
6/1+2+3+4+5+6
?
OpenStudy (anonymous):
probability of an event A happening in N number of experiments:
\[P(A)=\frac{\text{number of times A event happens}}{N}\]
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OpenStudy (anonymous):
so - what would the numerator be?
OpenStudy (anonymous):
event = the dice rolls a "1"
how many times does that happen?
OpenStudy (anonymous):
6.
OpenStudy (anonymous):
bingo
OpenStudy (anonymous):
oooh.
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OpenStudy (anonymous):
:)
OpenStudy (anonymous):
tyty!
OpenStudy (anonymous):
and the denominator is
OpenStudy (anonymous):
6. right?
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