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Mathematics 18 Online
OpenStudy (anonymous):

Based on the following results what is the experimental probability of rolling a 1? Outcome Frequency 1 6 2 2 3 2 4 3 5 2 6 0

OpenStudy (anonymous):

@garrett_payne

OpenStudy (anonymous):

Add up all the frequencies. Divide the frequency of the target outcome by the sum of all frequencies.

OpenStudy (anonymous):

let me try..

OpenStudy (anonymous):

so add up 1-6/6?

OpenStudy (anonymous):

No.. divide 6 by 6+2+2+3+...

OpenStudy (anonymous):

I know. 1-6 means all the numbers between 0 and 6.

OpenStudy (anonymous):

1+2+3+4+5+6/6

OpenStudy (anonymous):

?

OpenStudy (anonymous):

divide x by y means x / y not y / x

OpenStudy (anonymous):

I got '16'.

OpenStudy (anonymous):

It makes no sense for probability to be over 1.

OpenStudy (anonymous):

wait,sorry.

OpenStudy (anonymous):

can you give me the equation?

OpenStudy (anonymous):

o wait, you mean 6/1+2+3+4+5+6 ?

OpenStudy (anonymous):

probability of an event A happening in N number of experiments: \[P(A)=\frac{\text{number of times A event happens}}{N}\]

OpenStudy (anonymous):

so - what would the numerator be?

OpenStudy (anonymous):

event = the dice rolls a "1" how many times does that happen?

OpenStudy (anonymous):

6.

OpenStudy (anonymous):

bingo

OpenStudy (anonymous):

oooh.

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

tyty!

OpenStudy (anonymous):

and the denominator is

OpenStudy (anonymous):

6. right?

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