Question

I have the answer cansomeone please tell me what they got...
Find the derivative of
k(x)=tan(e^x)

Answer 1

\[k(x)=\tan (e^x)\]
\[k'(x)=\sec^2 (e^x)\times \frac{d}{dx} (e^x)\]
Did you do this?

Answer 2

yes and I got for an answer\[e^xcos^2(e^x)\]

Answer 3

it should be \(\sec^2 (e^x)\)

Answer 4

could it be cos^(e^x) I don't have sec as a choice

Answer 5

cos^2 e^x could be in the denominator
\[\frac{e^x}{\cos^2{e^x}}\]

Answer 6

ok yes I have that for one of my choices. So the answer that you just posted is another way in saying the answer correct.

Answer 7

yes since
\[\sec x =\frac{1}{\cos x}\]

Answer 8

ok gotcha thanks

Answer 9

Welcome :)