Two blocks, A and B, of masses m and 3m respectively are accelerated along a smooth surface by a force F applied to block A. What is the magnitude of the force exerted by block A on B during this acceleration?
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well first of all we are going to use Newton's second law of motion . Do you know what it states?
@Silverlark2 ?
The force should be \[F \div4\] according to newton's third law. Got a question like in CIE MCQ papers....
@mathslover yeah I do. F=ma. But how to apply?
Total mass = 3m + m = 4m put that : F = ma = (4m) a a = F/4m
Then apply Newton's Second Law specifically to block B to find the force acting on B. This gives:: \(F_B = m_B a_B\) \(F_B = 3m * F /4m\) Just remember that for block A, the forward force is but according to Newton's Third Law, block B exerts a force of on it. Therefore, its resultant force is , which keeps the acceleration of both blocks the same.
I took the answer from : http://www.thestudentroom.co.uk/showthread.php?t=370704 Check that there. it is nicely explained.
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