Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

how to use "In"?

OpenStudy (anonymous):

I have this question.. and I know i Have to use In... but dont know how Brooklyn has a goal to save $8,000 to buy a new entertainment system. In order to meet that goal, she deposited $4,132.79 into a savings account. If the account has an interest rate of 4.8% compounded quarterly, approximately when will Brooklyn be able to make the purchase?

OpenStudy (anonymous):

8000 = 4132.79(1+.048/12)^12*t 8000 = 4132.79(1.004)^12t (now I get stuck here..

OpenStudy (anonymous):

\[4132.79\times (1+\frac{.048}{4})^{4t}=8,000\]

OpenStudy (anonymous):

says QUARTERLY so be careful usually it is monthly

OpenStudy (anonymous):

yah u right... misread

OpenStudy (anonymous):

but then how do you continue... because that's when I get lost :/

OpenStudy (anonymous):

divide by 4132.78

OpenStudy (anonymous):

then use the change of base formula \[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]

OpenStudy (anonymous):

what actually In use for... like, I understand nothing at all about In... (In=log right) ?

OpenStudy (anonymous):

\[4132.79\times (1+\frac{.048}{4})^{4t}=8,000\] \[4132.79\times (1.012)^{4t}=8,000\] \[1.012^{4t}=8,000\div 4132.79\]

OpenStudy (anonymous):

and why is it use in this kind of formulas?

OpenStudy (anonymous):

\[1.012^{4t}=1.936\] rounded

OpenStudy (anonymous):

the to solve for \(4t\) use \[4t=\frac{\log(1.936)}{\log(1.012)}\]

OpenStudy (anonymous):

it doesn't matter what log you use

OpenStudy (anonymous):

mmm... but why log? like.. what is its function? I never understood when the teacher explained it...

OpenStudy (anonymous):

then i am sure i cannot explain it in a chat box here but basically \[b^x=y\iff \log_b(y)=x\]

OpenStudy (anonymous):

thats the formula right?

OpenStudy (anonymous):

it is a way to solve for a variable that is in the exponent

OpenStudy (anonymous):

mmmm.. got it.. the answer I got for the formula is t= 10.8 (then years and 8 month?)

OpenStudy (anonymous):

but you only have two logs on your calculator, \(\log_{10}(x)\) log base ten and \[\ln(x)=\log_e(x)\] which is log base e so if you want an actual decimal for an answer, you have to use \[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]

OpenStudy (anonymous):

in my calculator i have log2, log10, and In... can use any true? (I used In)

OpenStudy (anonymous):

in other words, to solve for the variable in the exponent, it is the log of the total divided by the log of the base that is how to solve for a variable that is in the sky

OpenStudy (anonymous):

haha got it... so my answer is 10.8... how do i convert that into years and months?

OpenStudy (anonymous):

sorry ... i got 13.8

OpenStudy (anonymous):

makes no difference, all logs are the same \[\log_b(x)=\frac{\log_a(x)}{\log_a(b)}\]

OpenStudy (anonymous):

got it... but how do you convert t = 13.85 into years and months?

OpenStudy (anonymous):

what does \(t\) represent?

OpenStudy (anonymous):

time...

OpenStudy (anonymous):

so im guessing it would be 13 years and 8 months right?

OpenStudy (anonymous):

in what units?

OpenStudy (anonymous):

years&months

OpenStudy (anonymous):

yes t is time in years

OpenStudy (anonymous):

but in the choices I've got there is no 13 years and 8 month... (they have 13 years and 10 months) so I'm guessing is that one.. but they also have 13 years and 5 months... so like, i want to know how to solve it correctly...

OpenStudy (anonymous):

Was 13 years and 10 months the correct answer?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!