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calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acidic, basic, or neutral? Show all work.
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Because [H+][OH-]= Kw = 1.0 x 10^-14 [H+]= Kw/ [OH-]= 1.0x 10^-14 / 1 x 10^-11 =1 x 10^-3 mol/L pH = - log [H+]= - log 1 x 10^-3 = 3 < 7 the solution is acidic
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