Question

find any points of discontinuity for the rational function y=(x+3)(x+7)(x+1)/(x-6)(x-5)


a.)x = –3, x = –7, x = –1

b.)x = –6, x = –5

c.)x = 3, x = 7, x = 1

d.)x = 6, x = 5

Answer 1

discontinuity will occur when you have vertical asymptotes.. i.e., when one of the following happens
1. a division by zero i.e., denomiator becomes "0"
2. there is a possibility of having square-root of a negative number.

Answer 2

in your case, it is the first condition that applies

Answer 3

what is the answer though cause i dont understand how to figure it out

Answer 4

set the denominator of the function to 0
\[(x-6)(x-5)=0\]
solve for x

Answer 5

so i would do like terms then divde omg idk i hate math

Answer 6

\[a\times b=0\]
only if \(a=0\) or \(b=0\). so,
\[x-6=0\qquad x-5=0\]
get it?

Answer 7

OOOOOOOOOOOOO

Answer 8

just observe that if x=6 or x=5, the denominator becomes zero. We don't no what happens when you divide something by zero (some say you get a black hole, but whatever.)
So, we just say we don't know what happens and don't mark that point on a graph.
So, the graph will look like a roller-coaster track that's missing a piece of the track (Oh! the horror).

Answer 9

ty both of u i have more lol

Answer 10

that's for another post :P

Answer 11

lol yeha