An object's position along the y-axis is given in meters by the equation vector(r) = (t^3-9t^2+24t+10)jhat, where t is in seconds. Where is the object located when it's acceleration is zero?

Question

experimentx · Answer

differentiate it twice and equate it to zero ... from here find the value of 't' and ... put this value of 't' in the original 'r' ...

anonymous · Answer

We are first going to find acceleration by differentiating twice "r" w.r.t. "t". Then we are going to put acceleration = 0 . From this we will be able to find the time when the acceleration will be zero. After that put the value of time in expression of r(t). As a result we will be able to find the location of object when its acceleration is zero