Describe the vertical asymptote(s) and hole(s) for the graph of y=(x-1)(x+3)/(x+3)(x-5)
[1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5
asymptote: x = 5 and hole: x = –3
asymptote: x = –5 and hole: x = 3
asymptotes: x = 5 and x = –3

Question

Describe the vertical asymptote(s) and hole(s) for the graph of   y=(x-1)(x+3)/(x+3)(x-5)
[1:06:17 PM] Akora: asymptote: x = –1 and hole: x = 5
asymptote: x = 5 and hole: x = –3
asymptote: x = –5 and hole: x = 3
asymptotes: x = 5 and x = –3

anonymous · Answer

why did you close the last question? It looks like you're pasting the questions from a test.

anonymous · Answer

no it aint from a testitis jux i did not neeit any more ani figured it out and  copy them from skype cause i am asng some oer fiends as well

anonymous · Answer

oh? so what was the answer to the last question?

anonymous · Answer

i got A

anonymous · Answer

OK that's right. If you're really not cheating, I'm sorry I doubted you.

anonymous · Answer

iaint it is a quick checkand idid the lesson jux d not undrsand it

anonymous · Answer

$$  y=\frac{(x-1)(x+3)}{(x+3)(x-5)}$$

anonymous · Answer

ok then. This question is exactly like the previous questions. Do the exact same thing.

anonymous · Answer

you can cancel the $x+3$ factor, which means it  has a "hole" at $x=-3$

anonymous · Answer

however you cannot cancel the factor of $x-5$ so it has a vertical asymptote at $x=5$

anonymous · Answer

figured it out