Question

Simplify 4∜48

a. 8∜3
b. 4∜3
c. 12∜4
d. 18∜2

Answer 1

well 48 = 16 x 3

and

16 = 2^4

so you can have

\[4\times \sqrt[4]{16 \times 3} = 4 \times \sqrt[4]{16} \times \sqrt[4]{3} = 4 \times 2 \times \sqrt[4]{3}\]

Answer 2

Okay, so it's a.
So the 4 over the radical doesn't really do anything?

Answer 3

it just means the 4th root... instead of the cube or square root

Answer 4

Oh, Okaay, thank you! (: