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Simplify quantity x squared plus 2 x over quantity 12 x plus 54 end quantity minus quantity 3 minus x over quantity 8 x plus 36
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\[\frac{x^2+2x}{12x+54}-\frac{3-x}{8x+36}\]
Does that look right?
\[\frac{x(x+2)}{6(2x+9)}-\frac{3-x}{4(2x+9)}\]
So we see that the common denominator is 12(2x+9)
How is it 12(2x+9) ?
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nevermind i know. lol
\[\frac{2}{2}\times\frac{x(x+2)}{6(2x+9)}-\frac{3}{3}\times \frac{3-x}{4(2x+9)}=\]
\[\frac{2x^2+4x}{12(2x+9)}-\frac{9-3x}{12(2x+9)}=\frac{2x^2+7x-9}{12(2x+9)}\]
\[\frac{2x^2+7x-9}{12(2x+9)}=\frac{(2x+9)(x-1)}{12(2x+9)}=\frac{x-1}{12}\]
Thank you so much.
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