Question

A solid gold cube with edge of 2" is melted down and recast as a cone with a 3" radius base.

Find the height of the cone.
A.) 8L(9pie) in.
B.) 2piein.
C.) 8L(3pie) in.

Answer 1

cube volume is r^3 so 2^3 = 8
now this is melted to cone whose volume is 1/3(pi r^2 h) = 3 pi h

so, 8 = 3 pi h

Answer 2

Can u find h from here

Answer 3

I have 1/3 (pi 8^2 h) = 3pih
then I have 21.3pih =3pih
so do I divide 3 from 21.3?

Answer 4

For cone radius is 3 not 8, 8 is the volume of cube

Answer 5

oh god, did I do my factoring right though, like how I solved it? Let me plug in a three.

Answer 6

okay, this is what I got :

Answer 7

I/3(pi3^2h) = 3pih
then I times 1/3 with 9
to get 3(pih) =3pih
so would it just be one when I divide it all out?

Answer 8

equate 3pi h to 8 as volume of both cube & cylinder are equal

8 = 3 pi h
h = 8/3 pi

Answer 9

okay, now I get you! and since it can't be factored out I leave it as 8/3pi? :D

Answer 10

yes thats the answer

Answer 11

thank you so much! this really helped a lot :) <3 here is a barfing gnome for your help! :D

Answer 12

thanks& yw:) always

Answer 13

You are a bad retrice thanks again! :) <3

Answer 14

*bad a$$*