Question

@SandeepReddy
Given the events below, determine which equation correctly calculates the probability of drawing two kings in a row from a standard 52-card deck, without replacement.

Event A: The first card drawn is a king.
Event B: The second card drawn is a king.

A. P(A n B) = P(A) * P(B|A)

B. P(A n B) = P(A) * P(B)

C. P(A n B) = P(A) * P(A|B)

D. P(A n B) = P(B) * P(B|A)

Answer 1

Sorry for the delay
Have you ever played or seen Cards?

Answer 2

Yeah

Answer 3

so how many kings wil be in a deck?

Answer 4

4

Answer 5

now probability from basic definition
\[P = \frac{ Favourable._.events }{ Total_.Number_.of_.Events }\]

Answer 6

for example, lets calculate the probability of getting even number when a 6 sided dice is thrown
Now in this case :
favourable events are 2,4,6 total 3
and total number of possible events are 1,2,3,4,5,6 total 6
so probability of getting even number when a 6 sided dice is 3/6 = 0.5

Answer 7

@ashleigh0519 interrupt whenever u feel that something is not clear to u

Answer 8

to continue

Answer 9

okay

Answer 10

Having said about calculating the probability then,
thats all u need to know to solve this problem :)

Answer 11

Now lets calculate the probability of event A:
favourable cases = 4
total events = 52

probability P(A) = 4/52 = 1/13

Answer 12

Is it B?

Answer 13

Now coming to the probability of B:

Answer 14

Now that already one King has gone in event A and furthermore, they said "without replacement"
so
Can u tell the favourable and total events for B?

Answer 15

P(B) = 3/52

Answer 16

You have at first total 52 cards, so total events in first event A is 52.
Now you took out a King from a deck of 52 cards in even A
so how many cards are there in total for event B?

Answer 17

50

Answer 18

how 50?

Answer 19

wait 51