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OpenStudy (anonymous):
OpenStudy (anonymous):
Figure out the \((x,y,z)\) coordinates for each point.
Then use the distance formula: \[
\overline{P_1P_2} = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}
\]
OpenStudy (anonymous):
I don't know how to find the points coordinates though since they're not exactly placed right
OpenStudy (anonymous):
Point A is \((2,2,3)\)
OpenStudy (anonymous):
Count the number of units in the \(x\) direction, then the number in the \(y\) direction, then in the \(z\) direction.
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OpenStudy (anonymous):
so is point A.. X >?
OpenStudy (anonymous):
\(A\) is 3 up, so \(z=3\)
OpenStudy (anonymous):
2 to the left, so \(x=2\)
OpenStudy (anonymous):
And 2 to the right so \(y=2\)
OpenStudy (anonymous):
Use the guide lines.
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OpenStudy (anonymous):
is point B.. (3,2,8)
OpenStudy (anonymous):
Oh wait... you're write the axis are messed up... I was wrong.
OpenStudy (anonymous):
yeah haha see!
OpenStudy (anonymous):
All that matters though is that you subtract the x's, the y's and the z's.
So even if you pick the wrong axis, as long as you're consistent.