Question

Find the perimeter of a square having two consecutive vertices at (7, 2) and (-3, 3).

Answer 1

Find the distance between those two points

Answer 2

That will give you the length of each side

Answer 3

Once you know the length of each side, you multiply by 4 to get the perimeter

Answer 4

so how do I exactly find the length im horrible at math.

Answer 5

you use the distance formula

d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

Answer 6

the first point is (x1,y1)

in our case, the first point is (7,2)

Answer 7

so (x1,y1) = (7,2)

Answer 8

which means

x1 = 7
y1 = 2

Answer 9

similarly, the second point is (-3, 3)

so

x2 = -3
y2 = 3

Answer 10

plug all that in and simplify

d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

d = sqrt( (2-7)^2 + (3-(-3))^2 )

d = sqrt( (2-7)^2 + (3+3)^2 )

I'll let you finish

Answer 11

oh wait, made a serious typo

Answer 12

let me fix it

Answer 13

d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

d = sqrt( (-3 - 7)^2 + (3 - 2)^2 )

Ok fixed

Answer 14

thank you so much

Answer 15

tell me what you get

Answer 16

101

Answer 17

now take the square root of that to get the exact distance to be \[\Large d = \sqrt{101}\]

Answer 18

so the exact perimeter would be \[\Large P = 4\sqrt{101}\]

since you multiply the side length by 4 to get the perimeter

Answer 19

you can use a calculator to get the approximate answer

Answer 20

that's what the answer is suppose to be thank you so much

Answer 21

yw