Mathematics
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OpenStudy (anonymous):
write each expression so that it contains only positive exponents
(2x)^-2/3y^-1
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jhonyy9 (jhonyy9):
do you know the property of exponents ?
jhonyy9 (jhonyy9):
so
a^-1 = ?
OpenStudy (anonymous):
1/a^1
jhonyy9 (jhonyy9):
yes so than for your exercise can using this property ?
jhonyy9 (jhonyy9):
(2x)^-2 = ?
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OpenStudy (anonymous):
1/(2x)^2
OpenStudy (anonymous):
I THINK
jhonyy9 (jhonyy9):
yes right but you can calculi it again ,continue ...
OpenStudy (anonymous):
1/4X ?
jhonyy9 (jhonyy9):
why 4x ?
no
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OpenStudy (anonymous):
CAUSE 2*2 IS 4
jhonyy9 (jhonyy9):
yes but check it again there are (2x)^2
OpenStudy (anonymous):
2(2x) I DONT KNOW
jhonyy9 (jhonyy9):
not 2*2x
this mean 2x*2x =
OpenStudy (anonymous):
4X
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jhonyy9 (jhonyy9):
why ?
2x*2x = 2*2*x*x =
OpenStudy (anonymous):
I DONT KNOW HOW TO SIMPLIFY 1/(2x)^2
jhonyy9 (jhonyy9):
so (2x)^2 = 2^2 *x^2 = ?
OpenStudy (anonymous):
2*X
OR
2*2X
jhonyy9 (jhonyy9):
2*2 = ?
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OpenStudy (anonymous):
4
jhonyy9 (jhonyy9):
x*x=?
OpenStudy (anonymous):
MY BAD 4*X
OR 4*2X
jhonyy9 (jhonyy9):
x*x= ?
OpenStudy (anonymous):
X
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jhonyy9 (jhonyy9):
why ?
OpenStudy (anonymous):
IS IT 2X
jhonyy9 (jhonyy9):
so than this mean that 2*2 =2 ?
OpenStudy (anonymous):
OK
jhonyy9 (jhonyy9):
not is ok
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OpenStudy (anonymous):
2*2 IS 4
jhonyy9 (jhonyy9):
yes so than x*x= ?
OpenStudy (anonymous):
ISNT X
jhonyy9 (jhonyy9):
so in your exercise there is (2x)^-2 = 1/(2x)^2 = 1/((2^2)(x^2)) = ?
OpenStudy (anonymous):
1/4(X^2)
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OpenStudy (anonymous):
or 1/4(x)^2
jhonyy9 (jhonyy9):
yes but without parantheses
1/(4x^2)
so this will be the first part
OpenStudy (anonymous):
ok
jhonyy9 (jhonyy9):
3y^-1 = ?
OpenStudy (anonymous):
1/3y^1
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jhonyy9 (jhonyy9):
no because there is just y on the exponent -1 and 3 have not exponent
yes ?
OpenStudy (anonymous):
oh
jhonyy9 (jhonyy9):
so there is 3*y^-1 =
y^-1 = ?
OpenStudy (anonymous):
1/3(y)^1
jhonyy9 (jhonyy9):
no
y^-1 = ?
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OpenStudy (anonymous):
its 1/y^1
jhonyy9 (jhonyy9):
ok
so above there is
3*y^-1 = 3*(1/y) = ?
OpenStudy (anonymous):
3y or do i do the distributive property
OpenStudy (anonymous):
3*3y distributive property way
jhonyy9 (jhonyy9):
no
how you multiplie a number with a fraction ?
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jhonyy9 (jhonyy9):
1
3 * ----- = ?
y
OpenStudy (anonymous):
oh its 3/y
jhonyy9 (jhonyy9):
yes
bravo
OpenStudy (anonymous):
lol
jhonyy9 (jhonyy9):
so after this calculi how will be your exercise ?
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OpenStudy (anonymous):
good
jhonyy9 (jhonyy9):
nice
jhonyy9 (jhonyy9):
can you rewriting the first fraction ?
OpenStudy (anonymous):
you want the orginal problem
OpenStudy (anonymous):
original
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OpenStudy (anonymous):
1/4x^2
jhonyy9 (jhonyy9):
1/(4x^2) / 3/y =
jhonyy9 (jhonyy9):
how you divide two fractions ?
OpenStudy (anonymous):
you want me to tell you how to divide fractions well flip the guy them multiply in this case its...
OpenStudy (anonymous):
then multiply
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OpenStudy (anonymous):
so we have 1/(4x^2) / 3/y
OpenStudy (anonymous):
1/(4x^2) / y/3
jhonyy9 (jhonyy9):
so you have wrote right with words but with fractions is wrong
OpenStudy (anonymous):
dont you flip the second guy
jhonyy9 (jhonyy9):
so you write there ,,multiplie " and write divide sign next (4x^2) ,why ?
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OpenStudy (anonymous):
oh forgot so its 1/(4x^2) * y/3
my bad
jhonyy9 (jhonyy9):
bravo
OpenStudy (anonymous):
:)
jhonyy9 (jhonyy9):
so the result ?
jhonyy9 (jhonyy9):
not is there the end of
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OpenStudy (anonymous):
\[ 1\over 4x^2\] * Y/3
jhonyy9 (jhonyy9):
1 y
----- * ------ = ?
4x^2 3
OpenStudy (anonymous):
1Y/12X^2
jhonyy9 (jhonyy9):
yes
y/(12x^2)
OpenStudy (anonymous):
SO THATS THE ANSWER
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OpenStudy (anonymous):
THANK YOU VERY MUCH
jhonyy9 (jhonyy9):
yw
was my pleasure
good luck
bye
OpenStudy (anonymous):
ARE YOU STILL THERE