Find the number of sides of a regular polygon if one interior angle is 60 degrees. A.) 3 B.) 4 C.) 5 D.) 6
I'm not so sure how to solve this, can someone please take me through this! :)
Do you know the formula for the sum of the measures of the interior angles of a polygon?
isn't it S= 180(n-2) ?
It is (n - 2)180, where n = number of sides. Since you have a regular polygon, the measure of each interior angle is the sum of the measures of the angles divided by the number of anlges.
If k is the interior angle, then we can use this formula k = 180(n-2)/n plug in k = 60 to get 60 = 180(n-2)/n 60n = 180(n-2) 60n = 180n - 360 I'll let you finish in solving for n
That gives you ((n - 2)180) / n, but this equals 60 in your problem, so you get ((n - 2)180)/n = 60 Now solve the equation for n
I got three when I divided 120 from 360, does that seem right? :O
n = 3 is correct
here's what it looks like |dw:1363907303588:dw|
that makes a lot more sense!! thank you so much!! :)
yw
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