@hartnn @jim_thompson5910 Think you can help me with 2 hard questions?
wut are they?
Consider the equation 7x + 3y = 42. Part 1: On your own paper, graph this equation using the slope-intercept method. In the space provided, explain, in words, each step of the procedure you used. Make sure to use complete sentences and correct grammar. Part 2: On your own paper, graph this equation using the intercepts method. In the space provided, explain, in words, each step of the procedure you used. Make sure to use complete sentences and correct grammar. ------------------------------------- Consider the line that passes through the point (-3, 2) and has a slope of 3. Part 1: Write the equation of this line using point-slope form. Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work.
to do part 1 for 7x + 3y = 42, you need to first solve for y
y is 14, right?
well you're doing the intercepts method, which is part 2
but part 1 wants 7x + 3y = 42 in slope intercept form first
you are correct though, the y-intercept is 14
y = x + 14?
7x + 3y = 42 3y = 42 - 7x 3y = -7x + 42 y = -7x/3 + 42/3 y = -7/3x + 14 so you were close
you forgot to divide the -7x by 3 to get -7/3x
oh yeah i always forget that
so y = -7/3x + 14 tells us that the y-intercept is 14
we start with the point (0,14) then using the slope, you go down 7 units, then go to the right 3 units to get to the point _____
(3,7) ?
good, you now have 2 points needed to graph this line
the two points are (0, 14) and (3, 7)
I'm really stumped on part 2.
part 2 is using the method we did beforehand
I'm horrible at the standard way
where you plug in x = 0 to find y then plug in y = 0 to find x remember that method?
yes.
that's what you're doing for part 2
okay, can you help on the second one?
sure
point-slope form is this y - y1 = m(x - x1)
m is the slope (x1, y1) is the point that the line goes through
we're given Consider the line that passes through the point (-3, 2) and has a slope of 3. so the slope is m = 3 the given point it goes through is (-3, 2), so (x1,y1) = (-3, 2) ----> x1 = -3, y1 = 2
so y - y1 = m(x - x1) y - y1 = 3(x - x1) ... plug in the slope y - 2 = 3(x - (-3)) ... plug in the point the line goes through y - 2 = 3(x + 3)
and you leave it like that because they want it in point-slope form
Awesome! Thanks.
parts 2 and 3 should be pretty straight forward, if not, let me know
okay, thanks so much :)
yw
Graphing the line using intercepts methods, that should be easy. Let's work on that
7x + 3y = 42 A line with x intercept a and y intercept b is of the form \[\frac x a +\frac y b=1\] So, here we'll divide the whole equation by 42 \[\frac{7x}{42}+\frac{3y}{42}=\frac{42}{42}\] \[\frac{x}{6}+\frac{y}{14}=1\] Do you understand this?
Somewhat, yes.
So tell me what are the x intercept and y intercept is here?
x- 6 and y-14 ?
Read my second post again
I don't think I understand it. I'm horrible at this form of it.
ash2326, I think when unheard wrote out "x- 6 and y-14" she meant that the x-intercept is 6 and the y-intercept is 14
Is it @unheard ?
Yes, That's what I meant.
I'm sorry, ok let's plot it
x intercept 6 y intercept 14 So we have two points \[(6, 0), (0, 14)\] Let's mark these on graph, and then we'll join them to get the line|dw:1363916049049:dw|
|dw:1363916095022:dw| I have joined the two points with a line, and extended it both the sides. Do you understand this?
Yes
Ok, let's work on the other one
Consider the line that passes through the point (-3, 2) and has a slope of 3. Point slope form of the equation It uses the definition of slope, do you know what's slope?
Hold on, I don't know how I would type the other one out.
I'll given you some idea
Steps 1) Divide the whole equation by 42, to get 1 on right side. 2) Simplify the left side to get the intercept form of the equation 3) In the denominator of x is the value of x intercept, mark the point (6, 0) on the graph 4) In the denominator of y is the value of y intercept, mark the point (0, 14) on the graph 5) Join the two points using a line and extend the line both sides to get the required line
Okay, got that down. :)
Ok, so what's slope?
Gah I can't figure it out :(
Slope is change in y over change in x Suppose you have two points (1, 2) and (3, 5) \[Slope=\frac{5-2}{3-1}=\frac 32\] The higher the slope, the steeper will be the line |dw:1363916825174:dw| Do you get some idea?
So 3/2? I can't really tell without the number line, thing. I'm usually better with visuals.
|dw:1363917019889:dw|
So yes?
Do you get it?
Yes, mostly. It's a bit late so I'm a bit out of it, but I think I get it. I just REALLY need help on 2 + 3 of the second one.
Line passes through the point (-3, 2) and has a slope of 3. Let's find the point slope form of the line Let (x, y ) be on the line, other point is (-3, 2) Writing the slope formula \[\frac{y-2}{x-(-3)}=3\] \[\frac{y-2}{x+3}=3\] This is the slope point form do you get it?
The second one is the point- slope form?
yes
You can cross multiply it \[y-2=3(x+3)\]
Join our real-time social learning platform and learn together with your friends!