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find the inverse alegrbraically: f(x)=4(^x)+8
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well how do you find the inverse? switch the x's and y's so y = 4^x + 8 becomes x = 4^y + 8 solve for y again
How do I solve for y?
subtract 8, then take the log base 4
x-8=log4?
you are solving for \(y\) right?
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im trying to find the inverse so i guess so
you have \[x = 4^y + 8\] subtract 8 get \[x-8=4^y\]
then take the log to solve for \(y\) and get \[\log_4(x-8)=y\]
So that is the complete answer?
as they say on tv, the "final answer"
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thank you
thanks for taking that one over @satellite I was pre-occupied :)
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