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The cosine of an angle whose terminal side falls in the second quadrant is -.1234. What is the sine of this angle? a. .9924 b. .1234 c. .5606 d. not enough information is given
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This is the exact same thing as before.
What did you learn from the previous problem?
(-.1234)^2+sin^2θ=1?
Use this identity to get sin(x). Then adjust the sign according to the quadrant. cos^2(x) + sin^2(x) = 1
Perfect. Now solve it
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I can't get this to come out right.
What did you get for -.1234 squared?
.01522756
What did you get when you subtracted that from 1?
.98477244
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What did you get when you hit your square root button?
.99235701237
Then why don't you select that answer?
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