The cosine of an angle whose terminal side falls in the second quadrant is -.1234. What is the sine of this angle?
a. .9924
b. .1234
c. .5606
d. not enough information is given

Question

The cosine of an angle whose terminal side falls in the second quadrant is -.1234. What is the sine of this angle?
 a. .9924 	
b. .1234 	
c. .5606 	
d. not enough information is given

mertsj · Answer

This is the exact same thing as before.

mertsj · Answer

What did you learn from the previous problem?

anonymous · Answer

(-.1234)^2+sin^2θ=1?

mathstudent55 · Answer

Use this identity to get sin(x). Then adjust the sign according to the quadrant.
cos^2(x) + sin^2(x) = 1

mertsj · Answer

Perfect.  Now solve it

anonymous · Answer

I can't get this to come out right.

mertsj · Answer

What did you get for -.1234 squared?

anonymous · Answer

.01522756

mertsj · Answer

What did you get when you subtracted that from 1?

anonymous · Answer

.98477244

mertsj · Answer

What did you get when you hit your square root button?

anonymous · Answer

.99235701237

mertsj · Answer

Then why don't you select that answer?