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Find teh absolute maximum and absolute minimum values of f on the given interval: F(x)= (x^(2)-1)^(3), [-1,2]. I know that I have to take the derivative, set that equal to 0, get the critical numbers, and put f(critical # and interval values) into original equation, but not sure how to take derivative on this one.
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chain rule
\[F'(x)=3(x^2-1)^2\times 2x\]
and how do you go from there, to the critical numbers? with other polynomials I just factored, so how do you do this one
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