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Mathematics 23 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

\[(5x^2 + 3x + 4) − (2x^2 − 6x + 3)\]distribute the minus sign and get \[5x^2 + 3x + 4 -2x^2 + 6x - 3)\]

OpenStudy (anonymous):

since you are only asked for B you job is to compute \(3+6\)

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

Add up 3x^2 - 9 and 2x + 9 So (3x^2 - 9) + (2x + 9) = ???

OpenStudy (anonymous):

5x^2 ?

jimthompson5910 (jim_thompson5910):

Sorry, I didn't see the first x Add x, 3x^2 - 9 and 2x+9 (x) + (3x^2 - 9) + (2x + 9) x + 3x^2 - 9 + 2x + 9 3x^2 + 3x + 0 3x^2 + 3x

jimthompson5910 (jim_thompson5910):

So after adding x, 3x^2 - 9 and 2x + 9, you will get 3x^2 + 3x, which is the total distance covered

OpenStudy (anonymous):

soo its 3x^2 + 3x

OpenStudy (anonymous):

add them up \[x+3x^2 - 9+2x + 9\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

they really reach for these "word problems" don't they ?

OpenStudy (anonymous):

they could have said "add the polynomials"

OpenStudy (anonymous):

LOLLL yess they do !! Can you guys do me onee more favor and just double check my work ?

jimthompson5910 (jim_thompson5910):

sure, what do you need to check

OpenStudy (anonymous):

ill write the 5 questions and show you my answers

OpenStudy (anonymous):

1. Simplify the following expression: (x − 8y) - (2x − 4y)If the final answer is written in the form Ax + By, what is the value of B? 2. Simplify: (4x − 6) − (5x + 1) 3. Simplify: (5x^2 + 3x + 4) + (5x^2 + 5x − 1) 4. Simplify: (4x − 6) + (3x + 6) & You helped me with the other 2 questions so i just put the ones i did on my own but these were my answers 1. 4y 2. -x-7 3. 10x^2 + 8x + 5 4. 7x+12

jimthompson5910 (jim_thompson5910):

ok one sec

OpenStudy (anonymous):

alrighty :] Thanks!!

jimthompson5910 (jim_thompson5910):

#1 the form is form Ax + By they want the value of B, so the answer cannot be 4y

jimthompson5910 (jim_thompson5910):

besides, -8y + 4y isn't 4y anyway you lost a sign somewhere

OpenStudy (anonymous):

Im bad with my signs /: negatives and positives -.- so confusing

jimthompson5910 (jim_thompson5910):

think of it like this -8 + 4 is the same as saying you're 8 dollars in debt, but you paid off $4 of that debt, so you're now 4 dollars in debt

jimthompson5910 (jim_thompson5910):

so that explains how -8 + 4 = -4

jimthompson5910 (jim_thompson5910):

and why -8y + 4y = -4y

OpenStudy (anonymous):

so itd be -4?

jimthompson5910 (jim_thompson5910):

B is -4, yep

OpenStudy (anonymous):

oki

jimthompson5910 (jim_thompson5910):

# 2 is correct, so congrats on that

OpenStudy (anonymous):

thanks :]

jimthompson5910 (jim_thompson5910):

#3 is close

jimthompson5910 (jim_thompson5910):

but not correct fully

jimthompson5910 (jim_thompson5910):

4 + (-1) is NOT 5

OpenStudy (anonymous):

-3?

jimthompson5910 (jim_thompson5910):

you have 4 dollars you add on 1 IOU

jimthompson5910 (jim_thompson5910):

you really have 4-1 = 3 dollars left (after you pay off the IOU)

jimthompson5910 (jim_thompson5910):

so that's why 4 + (-1) = 4 - 1 = 3

OpenStudy (anonymous):

oh alright ! i get it now.

jimthompson5910 (jim_thompson5910):

ok great

jimthompson5910 (jim_thompson5910):

# 4 is also incorrect

OpenStudy (anonymous):

sorry im blonde it takes a little bit.

jimthompson5910 (jim_thompson5910):

that's ok, just practice practice practice and hair color is just skin deep...has nothing to do with intelligence

OpenStudy (anonymous):

Lol yeah , im guessing #4 is 7x-12

jimthompson5910 (jim_thompson5910):

-6 + 6 = ???

jimthompson5910 (jim_thompson5910):

-6 means you are $6 in debt add on $6, so you are paying off $6 are you still in debt?

OpenStudy (anonymous):

nope itd be zero :o

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

-6+6 = 0

OpenStudy (anonymous):

so the answers just 7x?

jimthompson5910 (jim_thompson5910):

so you'd have 7x+0 or just 7x

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

ok aha :]

jimthompson5910 (jim_thompson5910):

just watch out for the signs and try not to forget any

OpenStudy (anonymous):

Ill think of the whole dollar thing next time i come to the signs , Thank you so much ! ! :]

jimthompson5910 (jim_thompson5910):

that's how I grasp negatives when I stumble a bit, and you're welcome

OpenStudy (anonymous):

Ive always troubled negatives , ive been taking algebra 1 for 3 years now , and havent passed . Im working so much harder now ,

jimthompson5910 (jim_thompson5910):

have you thought of using money terms for negatives before? I'm just curious how your teachers have taught negatives in the past

OpenStudy (anonymous):

ive heard of it but it was never enforced.

jimthompson5910 (jim_thompson5910):

I gotcha, so they brought it up (maybe once or twice), but never really stuck to it

OpenStudy (anonymous):

nopeeeee

OpenStudy (anonymous):

Im trying to finish up my work for next week so im ahead so i can spend my spring break with my younger sister , would you mind helping me with Multiplying monomials?

jimthompson5910 (jim_thompson5910):

sure I can help

OpenStudy (anonymous):

Choose the correct simplification of the expression d^3 • d^5. d d^15 d^2 d^8

jimthompson5910 (jim_thompson5910):

what did you get

OpenStudy (anonymous):

the arrow represents the degree of the monomials incase you didnt already know lol. and i think its d^15??

jimthompson5910 (jim_thompson5910):

^ means exponents, yes I know and no it's not d^15

jimthompson5910 (jim_thompson5910):

if you are multiplying expressions with the same base, then you add the corresponding exponents

jimthompson5910 (jim_thompson5910):

example x^2 times x^3 = x^(2+3) = x^5

OpenStudy (anonymous):

Alright that sounds a little better so d^8 ?

jimthompson5910 (jim_thompson5910):

because you can expand out the 'x' terms and you'll see 5 total x terms

jimthompson5910 (jim_thompson5910):

yep d^8

OpenStudy (anonymous):

alright you make this so much easier than the lesson lol

jimthompson5910 (jim_thompson5910):

lol glad to hear that

jimthompson5910 (jim_thompson5910):

glad it's finally clicking

OpenStudy (anonymous):

Choose the correct simplification of the expression (b^5)^4. b^9 b^625 b^20 b

OpenStudy (anonymous):

b^20 ?

jimthompson5910 (jim_thompson5910):

you got ???

jimthompson5910 (jim_thompson5910):

perfect

jimthompson5910 (jim_thompson5910):

you're a total pro at this

OpenStudy (anonymous):

HA i wish!

jimthompson5910 (jim_thompson5910):

you're just not giving yourself enough credit

OpenStudy (anonymous):

Choose the correct simplification of the expression (3x)^4. 81x^4 12x^5 81x^5 12x^4

jimthompson5910 (jim_thompson5910):

raise each piece to the 4th power

OpenStudy (anonymous):

81x^4 ?

jimthompson5910 (jim_thompson5910):

so you raise 3 to the 4th power to get ____

jimthompson5910 (jim_thompson5910):

yep, you got it

jimthompson5910 (jim_thompson5910):

see you know this stuff

OpenStudy (anonymous):

haha slowly but getting it !! :)

jimthompson5910 (jim_thompson5910):

well as long as you get there, that's all that matters

OpenStudy (anonymous):

Choose the correct simplification of the expression (x^2y)^2. x^4y^3 x^6y^6 x^4y^2 xy^4

jimthompson5910 (jim_thompson5910):

what did you get

OpenStudy (anonymous):

Havent even tried it yet lol .but im thinking the ^2 on the outside is going to distribute to the ones in the parenthese?

jimthompson5910 (jim_thompson5910):

yes that's one way of thinking about it basically you raise each part to the 2nd power

jimthompson5910 (jim_thompson5910):

x^2 to the 2nd power ----> x^2 * x^2 = x^(2+2) = x^4

jimthompson5910 (jim_thompson5910):

y to the second power -----> y^2

jimthompson5910 (jim_thompson5910):

or you can multiply the exponents multiply the outer by each of the inner

OpenStudy (anonymous):

so x^4y^2

jimthompson5910 (jim_thompson5910):

yep

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