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OpenStudy (anonymous):
\[(5x^2 + 3x + 4) − (2x^2 − 6x + 3)\]distribute the minus sign and get
\[5x^2 + 3x + 4 -2x^2 + 6x - 3)\]
OpenStudy (anonymous):
since you are only asked for B you job is to compute \(3+6\)
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
Add up 3x^2 - 9
and 2x + 9
So
(3x^2 - 9) + (2x + 9) = ???
OpenStudy (anonymous):
5x^2 ?
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jimthompson5910 (jim_thompson5910):
Sorry, I didn't see the first x
Add x, 3x^2 - 9 and 2x+9
(x) + (3x^2 - 9) + (2x + 9)
x + 3x^2 - 9 + 2x + 9
3x^2 + 3x + 0
3x^2 + 3x
jimthompson5910 (jim_thompson5910):
So after adding x, 3x^2 - 9 and 2x + 9, you will get 3x^2 + 3x, which is the total distance covered
OpenStudy (anonymous):
soo its 3x^2 + 3x
OpenStudy (anonymous):
add them up
\[x+3x^2 - 9+2x + 9\]
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
thanks!
OpenStudy (anonymous):
they really reach for these "word problems" don't they ?
OpenStudy (anonymous):
they could have said "add the polynomials"
OpenStudy (anonymous):
LOLLL yess they do !! Can you guys do me onee more favor and just double check my work ?
jimthompson5910 (jim_thompson5910):
sure, what do you need to check
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OpenStudy (anonymous):
ill write the 5 questions and show you my answers
OpenStudy (anonymous):
1. Simplify the following expression: (x − 8y) - (2x − 4y)If the final answer is written in the form Ax + By, what is the value of B?
2. Simplify: (4x − 6) − (5x + 1)
3. Simplify: (5x^2 + 3x + 4) + (5x^2 + 5x − 1)
4. Simplify: (4x − 6) + (3x + 6)
& You helped me with the other 2 questions so i just put the ones i did on my own but these were my answers
1. 4y
2. -x-7
3. 10x^2 + 8x + 5
4. 7x+12
jimthompson5910 (jim_thompson5910):
ok one sec
OpenStudy (anonymous):
alrighty :] Thanks!!
jimthompson5910 (jim_thompson5910):
#1
the form is form Ax + By
they want the value of B, so the answer cannot be 4y
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jimthompson5910 (jim_thompson5910):
besides, -8y + 4y isn't 4y anyway
you lost a sign somewhere
OpenStudy (anonymous):
Im bad with my signs /: negatives and positives -.- so confusing
jimthompson5910 (jim_thompson5910):
think of it like this
-8 + 4
is the same as saying
you're 8 dollars in debt, but you paid off $4 of that debt, so you're now 4 dollars in debt
jimthompson5910 (jim_thompson5910):
so that explains how -8 + 4 = -4
jimthompson5910 (jim_thompson5910):
and why -8y + 4y = -4y
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OpenStudy (anonymous):
so itd be -4?
jimthompson5910 (jim_thompson5910):
B is -4, yep
OpenStudy (anonymous):
oki
jimthompson5910 (jim_thompson5910):
# 2 is correct, so congrats on that
OpenStudy (anonymous):
thanks :]
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jimthompson5910 (jim_thompson5910):
#3 is close
jimthompson5910 (jim_thompson5910):
but not correct fully
jimthompson5910 (jim_thompson5910):
4 + (-1) is NOT 5
OpenStudy (anonymous):
-3?
jimthompson5910 (jim_thompson5910):
you have 4 dollars
you add on 1 IOU
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jimthompson5910 (jim_thompson5910):
you really have 4-1 = 3 dollars left (after you pay off the IOU)
jimthompson5910 (jim_thompson5910):
so that's why 4 + (-1) = 4 - 1 = 3
OpenStudy (anonymous):
oh alright ! i get it now.
jimthompson5910 (jim_thompson5910):
ok great
jimthompson5910 (jim_thompson5910):
# 4 is also incorrect
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OpenStudy (anonymous):
sorry im blonde it takes a little bit.
jimthompson5910 (jim_thompson5910):
that's ok, just practice practice practice
and hair color is just skin deep...has nothing to do with intelligence
OpenStudy (anonymous):
Lol yeah , im guessing #4 is 7x-12
jimthompson5910 (jim_thompson5910):
-6 + 6 = ???
jimthompson5910 (jim_thompson5910):
-6 means you are $6 in debt
add on $6, so you are paying off $6
are you still in debt?
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OpenStudy (anonymous):
nope itd be zero :o
jimthompson5910 (jim_thompson5910):
yep
jimthompson5910 (jim_thompson5910):
-6+6 = 0
OpenStudy (anonymous):
so the answers just 7x?
jimthompson5910 (jim_thompson5910):
so you'd have 7x+0 or just 7x
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jimthompson5910 (jim_thompson5910):
you got it
OpenStudy (anonymous):
ok aha :]
jimthompson5910 (jim_thompson5910):
just watch out for the signs and try not to forget any
OpenStudy (anonymous):
Ill think of the whole dollar thing next time i come to the signs , Thank you so much ! ! :]
jimthompson5910 (jim_thompson5910):
that's how I grasp negatives when I stumble a bit, and you're welcome
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OpenStudy (anonymous):
Ive always troubled negatives , ive been taking algebra 1 for 3 years now , and havent passed . Im working so much harder now ,
jimthompson5910 (jim_thompson5910):
have you thought of using money terms for negatives before? I'm just curious how your teachers have taught negatives in the past
OpenStudy (anonymous):
ive heard of it but it was never enforced.
jimthompson5910 (jim_thompson5910):
I gotcha, so they brought it up (maybe once or twice), but never really stuck to it
OpenStudy (anonymous):
nopeeeee
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OpenStudy (anonymous):
Im trying to finish up my work for next week so im ahead so i can spend my spring break with my younger sister , would you mind helping me with Multiplying monomials?
jimthompson5910 (jim_thompson5910):
sure I can help
OpenStudy (anonymous):
Choose the correct simplification of the expression d^3 • d^5.
d
d^15
d^2
d^8
jimthompson5910 (jim_thompson5910):
what did you get
OpenStudy (anonymous):
the arrow represents the degree of the monomials incase you didnt already know lol.
and i think its d^15??
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jimthompson5910 (jim_thompson5910):
^ means exponents, yes I know
and no it's not d^15
jimthompson5910 (jim_thompson5910):
if you are multiplying expressions with the same base, then you add the corresponding exponents
jimthompson5910 (jim_thompson5910):
example
x^2 times x^3 = x^(2+3) = x^5
OpenStudy (anonymous):
Alright that sounds a little better so d^8 ?
jimthompson5910 (jim_thompson5910):
because you can expand out the 'x' terms and you'll see 5 total x terms
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jimthompson5910 (jim_thompson5910):
yep d^8
OpenStudy (anonymous):
alright you make this so much easier than the lesson lol
jimthompson5910 (jim_thompson5910):
lol glad to hear that
jimthompson5910 (jim_thompson5910):
glad it's finally clicking
OpenStudy (anonymous):
Choose the correct simplification of the expression (b^5)^4.
b^9
b^625
b^20
b
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OpenStudy (anonymous):
b^20 ?
jimthompson5910 (jim_thompson5910):
you got ???
jimthompson5910 (jim_thompson5910):
perfect
jimthompson5910 (jim_thompson5910):
you're a total pro at this
OpenStudy (anonymous):
HA i wish!
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jimthompson5910 (jim_thompson5910):
you're just not giving yourself enough credit
OpenStudy (anonymous):
Choose the correct simplification of the expression (3x)^4.
81x^4
12x^5
81x^5
12x^4
jimthompson5910 (jim_thompson5910):
raise each piece to the 4th power
OpenStudy (anonymous):
81x^4 ?
jimthompson5910 (jim_thompson5910):
so you raise 3 to the 4th power to get ____
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jimthompson5910 (jim_thompson5910):
yep, you got it
jimthompson5910 (jim_thompson5910):
see you know this stuff
OpenStudy (anonymous):
haha slowly but getting it !! :)
jimthompson5910 (jim_thompson5910):
well as long as you get there, that's all that matters
OpenStudy (anonymous):
Choose the correct simplification of the expression (x^2y)^2.
x^4y^3
x^6y^6
x^4y^2
xy^4
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jimthompson5910 (jim_thompson5910):
what did you get
OpenStudy (anonymous):
Havent even tried it yet lol .but im thinking the ^2 on the outside is going to distribute to the ones in the parenthese?
jimthompson5910 (jim_thompson5910):
yes that's one way of thinking about it
basically you raise each part to the 2nd power
jimthompson5910 (jim_thompson5910):
x^2 to the 2nd power ----> x^2 * x^2 = x^(2+2) = x^4
jimthompson5910 (jim_thompson5910):
y to the second power -----> y^2
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jimthompson5910 (jim_thompson5910):
or you can multiply the exponents
multiply the outer by each of the inner