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Mathematics 13 Online
OpenStudy (anonymous):

What is the equation of the verticle asymptote of the graph: y=(1/x-3)+2

OpenStudy (johnweldon1993):

so it's \[y = \frac{ 1 }{ x-3 } + 2\] like that?

OpenStudy (anonymous):

yes exactly

OpenStudy (johnweldon1993):

okay....how do we find a vertical asymptote? we have a verticle asymptote when the denominator = 0 because any fraction with the denominator = 0 makes it not work right? so what number...makes YOUR denominator = 0?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

i think

OpenStudy (johnweldon1993):

correct :) so this graph will have a vertical asymptote at 3 so how do we write that as an equation "as your question asks" how do we make a verticle line in a graph? we make x=something right? so for a vertical line at 3 we would have x = 3

OpenStudy (anonymous):

Ohhh i see

OpenStudy (anonymous):

this is a lot easier than i thought thank you so much

OpenStudy (johnweldon1993):

lol no problem :)

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