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Mathematics 8 Online
OpenStudy (anonymous):

a_n=(3^(n+1))/(2^n)

OpenStudy (anonymous):

\[a _{n}=3^{n+1}/2^{n}\]

OpenStudy (anonymous):

wat shuld we do?

OpenStudy (anonymous):

my bad is it convergent

OpenStudy (anonymous):

Do u know what Convergency mean?

OpenStudy (anonymous):

Or what a divergency mean?

OpenStudy (anonymous):

see if you can show that it's a cauchy sequence

OpenStudy (anonymous):

yeah, the n in the exponents are throwing me off

OpenStudy (anonymous):

It is not convergent!

OpenStudy (anonymous):

yup it is not

OpenStudy (anonymous):

what test did you use in figuring that out

OpenStudy (anonymous):

it's a geometric series where |x| > 1

OpenStudy (anonymous):

I said That its not divegent using P series test!

OpenStudy (anonymous):

ok to sum it all up u can use those rules (p) and geometric if it is a sequence and a series

OpenStudy (anonymous):

\[a_n=3\left(3\over2\right)^n\] never converges

OpenStudy (anonymous):

so can you use the p series rules with sequences as well

OpenStudy (anonymous):

yeah!

OpenStudy (anonymous):

In maths, U can use anything anywhere as long as it satisfies them!

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