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a_n=(3^(n+1))/(2^n)
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\[a _{n}=3^{n+1}/2^{n}\]
wat shuld we do?
my bad is it convergent
Do u know what Convergency mean?
Or what a divergency mean?
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see if you can show that it's a cauchy sequence
yeah, the n in the exponents are throwing me off
It is not convergent!
yup it is not
what test did you use in figuring that out
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it's a geometric series where |x| > 1
I said That its not divegent using P series test!
ok to sum it all up u can use those rules (p) and geometric if it is a sequence and a series
\[a_n=3\left(3\over2\right)^n\] never converges
so can you use the p series rules with sequences as well
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yeah!
In maths, U can use anything anywhere as long as it satisfies them!
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