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Mathematics 17 Online
OpenStudy (anonymous):

How do you differentiate y=cospixsinpix

OpenStudy (anonymous):

first reduce the trig. function

OpenStudy (anonymous):

Would this use the product rule?

mathslover (mathslover):

Yes

OpenStudy (tkhunny):

I'm tempted to use this: \(\sin(2x) = 2\sin(x)\cos(x)\), entirely avoiding the Product Rule for the derivative.

OpenStudy (anonymous):

\[y=\frac{2\cos \pi xsin \pi x}{2}\] \[y=\frac{sin2 \pi x}{2}\] now apply chain rule

mathslover (mathslover):

\(\cfrac{d}{dx} (\cos \pi x)(\sin \pi x)\) Differentiating by using Product rule : \(\large\cos(\pi x)(\cos \pi x ) \ pi + \sin \pi x (-\ sin \pi x ) \pi\)

mathslover (mathslover):

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