Question

An oscillating spring's motion is modeled by x(t) = 5 + 2cos(t pi.3), where x is the position of the spring at time t. Determine the equilibrium point.

Answer 1

the equilibrium point is where x(t) = 0

Answer 2

So do I just plug in zero for t?

Answer 3

if you remove the + plus it'll help.

Answer 4

no, you set the argument equal to 0

Answer 5

so you solve for when cos(t pi .3) = 0

Answer 6

since cos = 0 at pi/2 and 3pi/2 we set tpi*.3 = pi/2 and 3pi/2

Answer 7

I typed it in wrong, its supposed to be t pi/3. So I set t pi/3 = pi/2 and solve?

Answer 8

correct.

Answer 9

we do not know that \(x(t)\) is the value from the equilibrium point.
so you may not set it to zero.
However, at equilibrium, \(v(t)\) is maximum

Answer 10

Ok, great. And so if it asks me to find x(5) then I plug in 5 for t?

Answer 11

yes

Answer 12

the question says, \(x(t)\) is position but does not say from where

Answer 13

x(t) is the equation of a spring, equilibrium is when cos(tpi/3) = 0

Answer 14

blah, v(t) max min, sorry tired. yeah.

Answer 15

ill just leave here T.T

Answer 16

Thanks for your help

Answer 17

@newlyblack do you have the answers?

Answer 18

No, it was from a test, and I'm trying to do test corrections.

Answer 19

so, what value did you get?