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Physics 18 Online
OpenStudy (anonymous):

Help needed

OpenStudy (anonymous):

http://screencast.com/t/v6XIdFASMPu @mathslover

OpenStudy (anonymous):

don't we have to care about the centre of mass ?

OpenStudy (anonymous):

yes.. you need to worry about centre of mass!

OpenStudy (anonymous):

you can't just do mgh here!

OpenStudy (anonymous):

initially U = mgh/2 finally U = mgh/4

OpenStudy (anonymous):

just wondering where does the energy go ??

OpenStudy (mertsj):

Something has to push the water up in the formerly empty container.

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

how is final mgh = mgh /4

OpenStudy (anonymous):

|dw:1364047929069:dw| potential energy in each container = (m/2)g(h/4) = mgh/8 total energy = 2 *mgh/8 =mgh/4

OpenStudy (anonymous):

can i know why initial PE = mgh / 2

OpenStudy (anonymous):

check out the figure in the question. The entire mass,m is in one container filled upto height, h. So center of mass is at height h/2. This gives U = mgh/2

OpenStudy (anonymous):

|dw:1364048812849:dw|

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