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don't we have to care about the centre of mass ?
yes.. you need to worry about centre of mass!
you can't just do mgh here!
initially U = mgh/2 finally U = mgh/4
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just wondering where does the energy go ??
Something has to push the water up in the formerly empty container.
hmm
how is final mgh = mgh /4
|dw:1364047929069:dw| potential energy in each container = (m/2)g(h/4) = mgh/8 total energy = 2 *mgh/8 =mgh/4
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can i know why initial PE = mgh / 2
check out the figure in the question. The entire mass,m is in one container filled upto height, h. So center of mass is at height h/2. This gives U = mgh/2
|dw:1364048812849:dw|
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