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Mathematics 8 Online
OpenStudy (anonymous):

[7.05] Find the geometric probability of throwing a dart and hitting the yellow ring. You may assume the dart will not miss the target entirely.

OpenStudy (anonymous):

Parth (parthkohli):

What is the total area the guy can hit?

Parth (parthkohli):

You know the radius, so you can determine what the total area of that dart-board is.

Parth (parthkohli):

OK, so what is the radius of the dart-board?

OpenStudy (anonymous):

11

Parth (parthkohli):

Good, and what is the area of the dart-board then?

OpenStudy (anonymous):

380.132

Parth (parthkohli):

That's correct. Now do you know how you could determine the area of that yellow thingy?

OpenStudy (anonymous):

treat it as one circle

OpenStudy (anonymous):

radius 5

Parth (parthkohli):

The yellow thingy is not a circle. You're partially correct :-)

Parth (parthkohli):

OK, so if you notice, the yellow thingy is the circle of radius 5 (as you said), MINUS the red thingy.

Parth (parthkohli):

And now if you find the area of that whole circle with radius 5, then subtract the area of that red circle with radius 2, you get the area of the yellow thingy.

Parth (parthkohli):

I hope I'm not confusing you, but can you do it?

OpenStudy (anonymous):

yah i got 65.97

Parth (parthkohli):

65.97 for?

OpenStudy (anonymous):

for the area of yellow portion

Parth (parthkohli):

Yeah, that is correct, approximately. Good job!

Parth (parthkohli):

All probabilities, including the geometric one, say this:\[{\rm Probability} = \dfrac{\mbox{Number of possible events we want}}{\mbox{Total number of possible events}}\]

Parth (parthkohli):

We can treat the areas as "events." So you just divide the area of the yellow thingy by the total area.

Parth (parthkohli):

And your geometric probability will turn out to be,\[P(\rm throw = yellow) \approx \dfrac{380.132}{65.97}\]

OpenStudy (anonymous):

thanks

Parth (parthkohli):

You're welcome!

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