Question

the product of two numbers is 56 when their sum is added to the sum of their squares we get 128. find the numbers.

Answer 1

plz....reply with whole equation..

Answer 2

Let the numbers be a and b.
a*b=56
(a+b)+(a^2+b^2)=128
(a+b)^2-2ab=a^2+b^2
(a+b)+(a+b)^2-2ab=128
(a+b)+(a+b)^2-2*56=128
(a+b)+(a+b)^2-112=128
(a+b)+(a+b)^2=128+112
(a+b)+(a+b)^2=240
Assume (a+b)=x
x+x^2=240
use quadratic equation and find x

Answer 3

thanks.....

Answer 4

have u found x

Answer 5

yup i got it
.....:)