standard normal variable, find the probability P(z> 0.59)
1 - z(0.59)
just gotta table up the z(0.59)
or negate the z, and find the table value of z(-0.59)
How do i what z is? thanks
I will put in the entire problem. the probability that z lies between -2.41 and z and 0 P(z>0.59) thanks
do you have a calculator, perhaps a ti83? if not, there are ztables written up that can be utilized
the probability that z lies between -2.41 and 0 is the cumulative probability from -2.41 to 0 of a mean of 0 and sd of 1
i have a t-83
under that stats button, you can hit the normalCDF function
did that
that function takes 4 arguments: lower, upper, mean, sd
to find the cumulative probability of z, from -2.41 to 0 normalCDF(-2.41,0,0,1) is the inputs
with any luck, you should get about .492
to find the cumulative probability of z > 0.59, its the same function lower is .59 and upper is say 9999 for some arbitrarily large upper value
ok, got the .492 and used it as the z score but is coming upw thi different answer what is p(z > .59)
z>.59 is about .2776 from the tables
ok, thanks you are best
youre welcome :)
Join our real-time social learning platform and learn together with your friends!