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Chemistry 17 Online
OpenStudy (anonymous):

how can i write this into an equation NaCl + KNO3 ->

OpenStudy (anonymous):

is it NaCl + KNO3 -> NaNO3 + KCl

OpenStudy (anonymous):

can there be a net ionic equation when there is no reaction?

OpenStudy (anonymous):

That's correct. No net ionic equation when there's no reaction.

OpenStudy (anonymous):

@lalokio thanks what about when it is NaCl + AgNO3

OpenStudy (anonymous):

^ Double replacement

OpenStudy (anonymous):

first do this: \[Na(NO)_3+AgCl\] then solve for the net ionic?

OpenStudy (anonymous):

NO_3 has -1 Na is in the alkali group so it has -1 Cl is in the halogen group so it has -1 Ag has -1 I think...

OpenStudy (anonymous):

@abb0t

OpenStudy (anonymous):

Ag is silver it has a positive charge, +1 and +2 are common.

OpenStudy (anonymous):

we then take out the spectators and we are left with Ag + Cl

OpenStudy (anonymous):

sorry yes +1

OpenStudy (anonymous):

I am just learning this stuff last week

OpenStudy (anonymous):

lol ts okay man this is some tough stuff hahaha can you look at my new question

OpenStudy (abb0t):

Yes, separate them by charge. plus goes with minus, minus with plus..you can look at your solubility table to tell whethere they form solid or w/e.

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