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OpenStudy (anonymous):
how can i write this into an equation NaCl + KNO3 ->
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OpenStudy (anonymous):
is it NaCl + KNO3 -> NaNO3 + KCl
OpenStudy (anonymous):
can there be a net ionic equation when there is no reaction?
OpenStudy (anonymous):
That's correct. No net ionic equation when there's no reaction.
OpenStudy (anonymous):
@lalokio thanks what about when it is NaCl + AgNO3
OpenStudy (anonymous):
^ Double replacement
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OpenStudy (anonymous):
first do this:
\[Na(NO)_3+AgCl\]
then solve for the net ionic?
OpenStudy (anonymous):
NO_3 has -1
Na is in the alkali group so it has -1
Cl is in the halogen group so it has -1
Ag has -1 I think...
OpenStudy (anonymous):
@abb0t
OpenStudy (anonymous):
Ag is silver it has a positive charge, +1 and +2 are common.
OpenStudy (anonymous):
we then take out the spectators and we are left with
Ag + Cl
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OpenStudy (anonymous):
sorry yes +1
OpenStudy (anonymous):
I am just learning this stuff last week
OpenStudy (anonymous):
lol ts okay man this is some tough stuff hahaha can you look at my new question
OpenStudy (abb0t):
Yes, separate them by charge. plus goes with minus, minus with plus..you can look at your solubility table to tell whethere they form solid or w/e.
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