In the regular triangular pyramid below, x = 5.9 mm and s = 14 mm.
*Note: Figure not drawn to scale.
What is the approximate surface area of the triangular pyramid?
I need to find the area of the bottom triangle I have the rest.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (goformit100):
What is the approximate surface area of the triangular pyramid? I need to find the area of the bottom triangle I have the rest.
OpenStudy (anonymous):
The 3 bigger triangles= 123.9 So what's the bottom?
OpenStudy (anonymous):
Surface area. The total of all the shapes area added up.
OpenStudy (anonymous):
@jim_thompson5910
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I narrowed the answer to two choices.
154.05 mm^2
138.97 mm^2
OpenStudy (anonymous):
@FlaCaLOL do you know how to do this?
OpenStudy (anonymous):
Got it!
138.97mm^2
jimthompson5910 (jim_thompson5910):
is the base an equilateral triangle?
OpenStudy (anonymous):
I believe.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
if so, then
A = (1/4)*s^2*sqrt(3)
A = (1/4)*5.9^2*sqrt(3)
A = 15.0731721528681
which is the area of the triangular base
jimthompson5910 (jim_thompson5910):
Add this to the lateral surface area you got to get
123.9 + 15.0731721528681 = 138.973172152869
which rounds to 138.97
jimthompson5910 (jim_thompson5910):
So you got it right (assuming the base is an equilateral triangle)