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Mathematics 16 Online
OpenStudy (anonymous):

In the regular triangular pyramid below, x = 5.9 mm and s = 14 mm. *Note: Figure not drawn to scale. What is the approximate surface area of the triangular pyramid? I need to find the area of the bottom triangle I have the rest.

OpenStudy (anonymous):

OpenStudy (goformit100):

What is the approximate surface area of the triangular pyramid? I need to find the area of the bottom triangle I have the rest.

OpenStudy (anonymous):

The 3 bigger triangles= 123.9 So what's the bottom?

OpenStudy (anonymous):

Surface area. The total of all the shapes area added up.

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

I narrowed the answer to two choices. 154.05 mm^2 138.97 mm^2

OpenStudy (anonymous):

@FlaCaLOL do you know how to do this?

OpenStudy (anonymous):

Got it! 138.97mm^2

jimthompson5910 (jim_thompson5910):

is the base an equilateral triangle?

OpenStudy (anonymous):

I believe.

jimthompson5910 (jim_thompson5910):

if so, then A = (1/4)*s^2*sqrt(3) A = (1/4)*5.9^2*sqrt(3) A = 15.0731721528681 which is the area of the triangular base

jimthompson5910 (jim_thompson5910):

Add this to the lateral surface area you got to get 123.9 + 15.0731721528681 = 138.973172152869 which rounds to 138.97

jimthompson5910 (jim_thompson5910):

So you got it right (assuming the base is an equilateral triangle)

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