What is the range of the function y = -x^2 + 1?

Question

anonymous · Answer

range and y are the same thing so find which number is the y

anonymous · Answer

y ≤ -1
y ≥ -1 I thnk this is the answer
y ≤ 1
y ≥ 1

anonymous · Answer

well the range is 1 but I don't know which way the sign is faced.

anonymous · Answer

$$\ge or \le $$

anonymous · Answer

well is there a sign that is originally in the problem?

anonymous · Answer

i think it is 
$$\le $$

anonymous · Answer

nope

anonymous · Answer

hm then I am not sure because usually those signs arent thrown in aren't thrown in last second

anonymous · Answer

ya

directrix · Answer

y = -x^2 + 1

- (x) ^2 takes on a value of 0 or a negative number for any real value of x.
So, the greatest value - (x)^2 can have is zero. Then, one is added to it. So, y = -x^2 + 1 maxes out when y = 1 and x is zero.

The range is the set of all possible values of y. y cannot be bigger than 1. So, the range is ?