Question

Please design a circuit that mixes V1 and V2 to produce Vout such that
Vout = 1/2*v1 + 1/6*v2
The resulting output should be similar to that shown in Figure 1. The maximum value of the output is approximately 667mV and the minimum value is approximately −167mV.

Answer 1

Can anyone please explain how to do it?

Answer 2

The mixer circuit should look like this

Answer 3

How did you get it?

Answer 4

@Nurali ?

Answer 5

Its not right, Can u please reconsider it?

Answer 6

Impossible to do with this circuit. Imagine the resistors are different (R1 for V1 and R2 for V2) In this case, the output is:
\[V=V_1/(1+R_1/R2)+V_2/(1+R_2/R1)\]In order tu comply with the requirements we have to solve:
\[1+R_1/R_2=2\] and \[1+R_2/R_1=6\] which has no solution as the first relation leads to \[R_1=R_2\]and the second one to \[R_2=5R_1\] and you can see they are not compatible

Answer 7

Now place a resistor R between the R1-R2 junction (say, the node where you want to get V from) and ground. Find the relationships with V1 coefficient, V2 coefficient and the ratio of V1 and V2 coefficients (1/2 divided by 1/6, that is 3). You will get R1 and R2 as a function of R

Answer 8

THIS IS THE SOLVED LAB 2 PLZ DO TELL ME THE IL MIN AND IL MAX VALUES

Answer 9

LAB 2 SOLVED