differentation find increasing,decreasing,maximum and minimum f(x)=x-13/x^2-25
\[f(X)=\frac{ x-13 }{ x^{2}-25 }\]
I guide you only, take derivative first, tell me the result
1. differentiate using quotient rule OR 2. convert the fraction to a product and use product rule.
good friend!!!
I like the second method.. and here it goes \[f(x)=\frac{x-13}{x^2-25}=(x-13)(x^2-25)^{-1}\\ f'(x)=(x-13)\left[(-1)(x^2-25)^{-2}{d\over dx}(x^2-25)\right]+(1)(x^2-25)^{-1}\\ f'(x)={-2x(x-13)\over(x^2-25)^2}+{1\over x^2-25}\]
you may simplify by taking the common denominator
\[\frac{ (x-1)(x-25) }{ (x^2-25)^2 }\]
how to find its stationary point???
at a stationary point \(f'(x)=0\)
at x=1, x=25 and x =5 is that right???
there seem to be only two values, not 3
which one is incorrect???
x=5 are incorrect right
right
thank u all
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