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can someone please show me how to do this? solve the equation: 2cosx+1=0
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cos x = -1/2 so can you tell me the values of x satisfying the above eq in the range[0, 2pi)?
\[2 \cos x +1 = 0\]\[2 \cos x =-1 \]Divide 2 on both sides, \[\cos x = -\frac12\]Then follow above^
thank you
So why are you reposting this?
i'm not sure what to do after cosx=-1/2
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Are you familiar with the unit circle?
yes
And you know that the cosine is like x?
yes
So find the two angles on the unit circle which have x coordinate - 1/2
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11pi/6 and 7pi/6?
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