Question

If sinA=5/6, where angle A is in Quadrant 1, find the exact value of sin (1/2A)

Answer 1

1,172cm(2)

Answer 2

I assume that's sin (.5A). There is a half-angle formula for sin.

Answer 3

so can you please help me solve the problem?

Answer 4

\[\cos^2A+\sin^2A=1\]\[\cos A=\sqrt{1-\sin^2A}\]
From this \(\cos A\) can be found
u can find \(\cos A\).
Then use
\[\cos A=1-2\sin^2(\frac{ 1 }{ 2 }A)\]\[\sin \frac{ 1 }{ 2 }A=\sqrt{\frac{ 1-\cos A }{ 2 }}\]
from this u can find
\[\sin \frac{ 1 }{2}A\]
Does that help?

Answer 5

but do u have an answer?

Answer 6

Mine is at the very top

Answer 7

did u use the half-angle formula because i'm getting a radical?

Answer 8

what r u getting?