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Calculus1 16 Online
OpenStudy (anonymous):

does any one know rolles theorem? please help

OpenStudy (anonymous):

f(x)= 5-12x+3x^2 [1,3] vertify that function staifies the three hyp of rooles thorem

OpenStudy (anonymous):

check that \(f(1)=f(3)\) first

OpenStudy (anonymous):

since it is a polynomial, it satisfies all the other parts of the hypothesis namely: it is differentiable on \((1,3)\) and it is continuous on \([1,3]\) it must be, since it is a polynomial

OpenStudy (anonymous):

of all those conditions are met, the the conclusion is there is a number \(c\in (a,b)\) with \[f'(c)=0\]

OpenStudy (anonymous):

*if

OpenStudy (anonymous):

in fact, since you have a quadratic, not only does \(c\) exist, but it must be right in the center of \((1,3)\) i.e. \(c=2\)

OpenStudy (anonymous):

why c is 2?

OpenStudy (anonymous):

did you check that \(f(1)=f(3)\)?

OpenStudy (anonymous):

yes i got this one too. but its 3 not 2..?

OpenStudy (anonymous):

i just did and i got \(-4\) for both

OpenStudy (anonymous):

now take the derivative, set it equal to zero and solve i bet you get \(2\)

OpenStudy (anonymous):

it has to be if you have a quadratic

OpenStudy (anonymous):

in general the solution does not have to be in the center of the interval, but it does if you have a quadratic in any case for this one you get \[-12+6x=0\] and so \(x=2\)

OpenStudy (anonymous):

O i got it thank you! its not about math question..but do you know how to minimize the screen? this webpage is way too big all of sudden

OpenStudy (anonymous):

no idea i just go to the top and minimize

OpenStudy (anonymous):

it worked. thank you!!!

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