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Mathematics 8 Online
OpenStudy (anonymous):

please help to find critical and increasing and decreasing intervals, i am really confused!

OpenStudy (anonymous):

OpenStudy (moonlitfate):

Hi there! Hopefully, I can help you out and not confuse you. :D First all of do you know how to find critical numbers of a function at all?

OpenStudy (anonymous):

slightly yes

OpenStudy (moonlitfate):

Give a minute. :) Working out the derivative of that function.

OpenStudy (moonlitfate):

Okay, well, what do you know so far?

OpenStudy (anonymous):

it should be 56x/(x^2+4)^2

OpenStudy (moonlitfate):

Okay, I figured out the derivative and the critical numbers of the function. Yeah, got that, too.

OpenStudy (moonlitfate):

Basically to find out the intervals where a function is increasing, you're going to use any critical numbers -- where f'(x) = 0 or any numbers where the function undefined to make test intervals. Does that make sense?

OpenStudy (anonymous):

so first I have to find ciritcal points. How do i do that?

OpenStudy (moonlitfate):

Okay. Basically to find critical points, you are going to set f'(x) = 0 and solve for x. That will give you your critical points.

OpenStudy (anonymous):

so it would be 56x/(x^2+4)^4=0?

OpenStudy (anonymous):

what shall i do next step?

OpenStudy (moonlitfate):

\[f'(x) = \frac{ 56x }{ (x^2+2)^2 }\]\[\frac{ 56x }{ (x^2+4)^2 } = 0\]\[(x^2+4)^2*\frac{ 56x }{ (x^2+4)^2 } = 0*(x^2+4)^2\] \[56x = 0\] \[x = 0\]

OpenStudy (anonymous):

thats cool. so ciritcal point is zero.?

OpenStudy (moonlitfate):

So, when can use x = 0 to divide the domain of f(x) and test the f'(x) for values of x on those intervals.

OpenStudy (moonlitfate):

Yes. :)

OpenStudy (moonlitfate):

In the case of this function, the domain is:\[(-\infty, \infty)\] So, you would use x = 0 to divide that into two intervals. \[(-\infty, 0), (0, \infty)\]

OpenStudy (moonlitfate):

With me so far?

OpenStudy (anonymous):

ook, when you are talking about domain, you are taking about domain of f(x)'?

OpenStudy (moonlitfate):

Yes. The domain of the original function, f(x).

OpenStudy (anonymous):

origional function, ok.

OpenStudy (anonymous):

sorry I have to go, but I will be back around 45 mins.

OpenStudy (moonlitfate):

No problem. Sorry for taking so long. I'll put up what I have, though.

OpenStudy (moonlitfate):

Basically what you are going to do next, is pick values of x within your intervals and test f'(x). You're going to evaluate f'(x) at the values you have chosen. The sign on derivative is going to tell if the function is increasing or decreasing on that interval. If the sign of f'(x) is negative, then the function f(x) is decreasing on that interval. If the sign of f'(x) is positive, then the function f(x) is increasing on that interval.

OpenStudy (moonlitfate):

I've attached a table showing what I did, as well as the graph of the function to verify that my answers. I hope that it helps. If you have need more help let me know. :)

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