in each part, use the given inner product on R^2 to find || w|| where w=(-1,3) a)the Euclidean inner product b) the weighted Euclidean inner product = 3u1v1+2u2v2 where u =(u1,v1) and v=(v1,v2) c) the inner product generated by the matrix (top: 1,2; bottom: -1,3) I don't understand the question. Please tell me what they want me to do?
\[ ||w||=<w,w>=3(w_1)(w_1)+2(w_2)(w_2) \]
thats part (b)
got it
par a
= sqtr(10)
I'm ok withc
(c): obtain w' \[w'=\left[\begin{matrix}1&2\\-1&3\end{matrix}\right]\left[\begin{matrix}-1\\3\end{matrix}\right]\]
a) is it right? I got c) (know how to get)
let me rearrange mine: a) = sqr(10) . is it right? everybody?
b) and c) is quite easy, I got it. just want to confirm a
if you take square-root, it is the L2 norm!
what if in part b, it's not +, but -? I mean what if the problem ask for finding d(u,v) , base on the inner product they give out <u, v> = 3u1v1+2u2v2
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