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3x^2+9x=84 solve
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x=7,4
no can you relook?
@happypancakes
The quadratic formula can be used to solve such a problem \[\boxed{ax^2+bx+c=0\qquad\implies\qquad x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}\]
so first get \(3x^2+9x=84\) into the right form (with everything on the left hand side ) then can you tell me what \(a,b,c \) are ?
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2.60=x
nope
It can't be 2.59 because that equals 83.etc. Can't be above 2.60 or its too much. You'll have to round. Therefore it has to be 2.60
when you use the quadratic formula you'll find x=4,-7
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