Question

Please help! problem in description

Answer 1

Get rid of the denominators, first :)

Answer 2

that's the part i have trouble with

Answer 3

I'm writing it here, for your convenience...
\[\LARGE \frac{3}{x}+\frac{3}{x-2}=1\]

Answer 4

thx

Answer 5

The most straightforward way to get rid of denominators is by multiplying the expression by said denominator...

Answer 6

So... let's multiply everything by x...
\[\LARGE x\left(\frac3{x}+\frac3{x-2}\right)=x(1)\]

Answer 7

so i multiply both sides by by (x)(x-2) ?

Answer 8

Actually, yes :)
Go for it, champ ^.^

Answer 9

so so far i have \[3x-6+3x=3x^2 -6\]

Answer 10

is that correct?

Answer 11

How did you get 3x²-6 on the other side?

Answer 12

As I recall, you only multiplied everything by x(x-2) = x² - 2x

Answer 13

oohh i got mixed up

Answer 14

Error in calculation. Requesting rectification of the situation. Stand by... ^.^

Answer 15

\[3x−6+3x=x^2−2\] so it's this?

Answer 16

Still no ;)
Remember... x(x-2) = x² - 2x

Answer 17

And yet you only have x² - 2 on the right-hand side of your equation...

Answer 18

im confused, this is waht i did. i first multiplied both sides by x and got \[3+(3x/x-2)=x\] then i multiplied it by x-2 and got \[3x-6 + 3x = x^2-2\]

Answer 19

Start with this...
\[\Large 3+\frac{3x}{x-2}=x\]Multiplying by x-2, you get...
\[\Large (x-2)\left(3+\frac{3x}{x-2}\right)=x(x-2)\]

Answer 20

\[3x-6+3x=x^2-2x\]

Answer 21

And ther eyou go :)
Now just solve it. Using Quadratic Formula.

Answer 22

kk i see, thanks