The center and vertices of the hyperbola y^2-4x^2-6y-8x-11=0 are:

A) center (3, -1)
vertices (-1, 1) and (7, -1)
B) center (-1, 3)
vertices (-1, 7) and (-1, -1)
C) center (3, 1)
vertices (5, 1) and (1, 1)
D) center (3, 1)
vertices (3, 5) and (3, 3)

Question

The center and vertices of the hyperbola y^2-4x^2-6y-8x-11=0 are:


A) center (3, -1) 
vertices (-1, 1) and (7, -1) 
B) center (-1, 3) 
vertices (-1, 7) and (-1, -1) 
C) center (3, 1) 
vertices (5, 1) and (1, 1) 
D) center (3, 1) 
vertices (3, 5) and (3, 3)

tkhunny · Answer

Complete the square in both x and y.

maddss · Answer

what?

tkhunny · Answer

You're saying you've never "Completed the Square"?

y^2-4x^2-6y-8x-11=0

Rearrange

y^2 - 6y - 4x^2 - 8x - 11 = 0

Regroup and set up

(y^2 - 6y + ____) - 4(x^2 + 2x + ____) = 11 + ____ - 4(____)

Fill in the blanks!

directrix · Answer

@maddss Did you see the graph for this? Maybe @tkhunny will give a solution. http://openstudy.com/users/maddss#/updates/514e1555e4b0ae0b658aed6b