Question

A simple harmonic motion has amplitude 6 and circular frequency of 100pi radians per second. Write a formula for the displacement d at any time t. What is the period of the simple harmonic motion?

Answer 1

does this help ?

Answer 2

http://bit.ly/11B0lsk

Answer 3

it does not help at all

Answer 4

haha
learn to laugh ;p

Answer 5

SHM : x=Acos(wt)

Answer 6

So here, You are give amplitude and frequency ..

Do you know the relation b/w angular frequency and frequency?
-- w=2 x pi x (freq)

Also, Time period is the reciprocal of frequency.

Now you have all the necessary information to solve it :) :D

Answer 7

SHM is a sine or a cosine function each of which has a maximum and minimum value of +1 and -1 respectively. Lets choose the sine function and give it an amplitude of 6 by multiplying by 6 and an angle in radians which is the circular (angular) frequency multiplied by t (the time in seconds). Therefore we get
\[f(t)=6\sin 100 \pi t\]