Question

x^2+y^2=52; (-4,6)

Answer 1

remember the formula before :
x1x + y1y = r^2

Answer 2

just plug x1=-4, y1=6, and r^2=52

Answer 3

Will the given point always be on the points for the circle?

Answer 4

not always!

Answer 5

first, check is the point given satisfies to equation of that circle
x^2 + y^2 = 52
(-4)^2 + 6^2 = 52
16 + 36 = 52
LHS = RHS
so, point (-4,6) on the circle

Answer 6

I get y=(2/3)x+26/3

Answer 7

because point(-4,6) is a point on circle so we use the formula tangen line of circle with the centre (0,0) and radius r:
x1x + y1y = r^2

ur equation :
-4x+6y = 52
6y = 52 + 4x
y = (2/3)x + 26/3

U ARE RIGHT !

Answer 8

@RadEn Thank you :)

Answer 9

very welcome :)