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Calculate the enthalpy of atomization per unit volume for Rb(s). Express your answer in kJ/m3. rubidium gas has a heat of formation of 80.9 kJ/mol.
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how? ,@srbirajdar88
82.0/55.74(1*10^-6)=1.47*10^6 enthalpy of atomization/volume = enthalpy of atomization per mole/volume per mole This is how I found it before the additional note
thanks @mikalika
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