Ask
your own question, for FREE!
Mathematics
20 Online
OpenStudy (anonymous):
This can be factored. but how ?
x^4 + 2 x^2 y^2 + 9y ^4
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Mertsj
OpenStudy (mertsj):
What makes you think it can be factored?
OpenStudy (mertsj):
There are no factors of 9 whose sum is 2
OpenStudy (anonymous):
my profesor said there is a technique for this, but not quad. formula
OpenStudy (mertsj):
So you want the factors based on the roots?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
he said diff of squares
OpenStudy (anonymous):
we thought its prime. but he insisted that it can.
OpenStudy (mertsj):
(x^2-2xy+3y^2)(x^2+2xy+3y^2)
according to wolframalpha.com
OpenStudy (anonymous):
@amistre64 @jim_thompson5910
OpenStudy (anonymous):
how about x ^4 + 4y ^4 ? can you show process ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Luis_Rivera
OpenStudy (mertsj):
ok. Try this trick:
\[x^4+2x^2y^2+9y^4=x^4+6x^2y^2+9y^4-4x^2y^2=(x^2+3y^2)^2-(2xy)^2\]
OpenStudy (anonymous):
so i would expand the ( x^2 +3y^2)^2 right ?
OpenStudy (mertsj):
No. You would replace (x^2+3y^2 ) with a. Replace 2xy with b. Then you would factor that and after you factored it, resubstitute.
OpenStudy (mertsj):
|dw:1364231753336:dw|
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!