Question

Find y" for y = sin^2(x)

Answer 1

Did you already find y'?

Answer 2

so i'm just taking the derivative here right?

Answer 3

Yes, you are finding the second derivative so just take the derivative of the function and then take the derivative of the derivative of the function :p

Answer 4

okay thanks!

Answer 5

can u show it please?

Answer 6

\[y' = 2\sin(x)\cos(x)\]and then\[y'' = \frac{ dy }{ dx } 2\sin(x)\cos(x) = 2(\cos^2(x) - \sin^2(x))\]

Answer 7

ok