Question

How would I simplify (3b^3/2a^3b^5)^4

Answer 1

use this rule: \((a^n)^m=a^{nm}\)

Answer 2

u tried @maddiemaze ??

Answer 3

I'm not sure how to apply the rule

Answer 4

\[\huge\frac{ 81a^{12}b^{32} }{ 16 }\]

Answer 5

i do the nominator for you: \(81b^{12}\)

Answer 6

\[\huge (\frac{ a }{ b })^m=\frac{ a^m }{ b^m }\]

Answer 7

okay @myko if the numerator is 81b^12 would the denominator be 16b^32

Answer 8

no

Answer 9

@deena123 would one of the letters be at the bottom?

Answer 10

\(2^4(a^3)^4(b^5)^4=?\)

Answer 11

sorry answer should be \[\huge (\frac{ 3b^3 }{ 2a^3b^5 })^4=\frac{ 81 }{ 16a^{12}b^8 }\]

Answer 12

@myko ??

Answer 13

that's the denominator

Answer 14

that should be the answer!!

Answer 15

so: \((3b^3/2a^3b^5)^4=\frac{81b^{12}}{16a^{12}b^{20}}=\frac{81}{16a^{12}b^8}\)

Answer 16

Thanks guys

Answer 17

yw