Question

PLEASE HELP!!!!!!!!!!!!
Write an equation in standard form for the circle.

Answer 1

A)(x + 3)2 + (y + 6)2 = 16
B)(x – 3)2 + (y + 6)2 = 16
C)(x + 3)2 + (y – 6)2 = 16
D)(x – 3)2 + (y – 6)2 = 16

Answer 2

@Rohangrr can u help me here?

Answer 3

yo!

Answer 4

You want it step wise

Answer 5

Sort out the x's and y's together and put the number on the right
\[x^2 - 2x + y^2 + 6y = -10 \]
Complete the squares by taking the number in front of the letter (say -2), take half of it (-1) and square it (-1 squared is 1)
Add this number to the left and the right
\[x^2 - 2x + 1 + y^2 + 6y + 9 = -10 + 1 + 9 \]
\[x^2 - 2x + 1 + y^2 + 6y + 9 = 0 \\ (x - 1)^2 + (y + 3)^2 = 0\]

Answer 6

Can u do i now?

Answer 7

i= it

Answer 8

uhm im confused on where you got all those numbers from the graph???

Answer 9

lets make it easy

Answer 10

See the graph

Answer 11

Now sort out all the X & Y that is covered by the circle

Answer 12

-4 and -8 if you see the graph

Answer 13

that was x and y's are - -4 and -2

Answer 14

ok

Answer 15

now @sh9down45 see the equation above and solve it? isn't it easy now

Answer 16

good! all the best

Answer 17

Hope the matter I'd put up helps u

Answer 18

its helping, thank you im solving the prob now. thank you sooo much!!!

Answer 19

no problem

Answer 20

I got (x + 3)2 + (y + 6)2 = 16 is that right???